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I can’t understand the current sampling circuit, so please advise.

Hardware design
August 12, 2020 by Jackson 501

On the left side of the figure is a chemical sensor, with current flowing between the 2 pins. Ask experts to teach the working principle of the schematic diagram, whether R19 needs to use a high-precision sampling resistor. Thank you very much!

QQ图片20171110211127.png

All Comments

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Jessica Posted on August 12, 2020

This is an oscillating circuit, the chemical sensor composition changes, causing the oscillation frequency to change.

The size of R19 affects the sensitivity of the sensor. This circuit should have a calibrated (positive) adjustable resistance.

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Samantha Posted on August 12, 2020

This is a sensor amplifier circuit. The voltage signal output by the sensor is amplified by the operational amplifier at pin 3.

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Ella Posted on August 12, 2020

Amplifier 2 and 3 pins are GND, the sensor current flows through the network composed of C8, R15, R14 and R17, the current signal is converted into a voltage signal, R18 and C16 form an RC low-pass filter output.

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Sarah Posted on August 12, 2020

Coincidentally, the circuit used in a project I have recently used is similar to yours. When I was making a carbon monoxide sensor, the carbon monoxide sensor used was a current source. The current was converted into a voltage through the transconductance of the operational amplifier and output to the AD port of the microcontroller.

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